2∫0cΔt11+(axc2+vc)2dx+2∫0cΔt21+(axc2+v+aΔt1c)2dx+(2v+a(Δt′+Δt1+Δt2))(Δt′−Δt1−Δt2)=2cΔt′
Δt′=Δt(c2+v2−vc−v),M=m(c2+v2−vc−v),L=l(c−vc2+v2−v)
a=dvdt,F≈Ma(1+3v2c),P≈Mv(1+3v4c),E≈12Mv2(1+vc)